Each iteration of for_each_available_child_of_node puts the previous
node, but in the case of a return from the middle of the loop, there is
no put, thus causing a memory leak. Hence add an of_node_put before the
return in two places.
Issue found with Coccinelle.
Signed-off-by: Nishka Dasgupta <nishkadg.linux@xxxxxxxxx>
---
drivers/staging/mt7621-pci/pci-mt7621.c | 5 ++++-
1 file changed, 4 insertions(+), 1 deletion(-)
diff --git a/drivers/staging/mt7621-pci/pci-mt7621.c b/drivers/staging/mt7621-pci/pci-mt7621.c
index 89fa813142ab..2e37fd136ab8 100644
--- a/drivers/staging/mt7621-pci/pci-mt7621.c
+++ b/drivers/staging/mt7621-pci/pci-mt7621.c
@@ -400,6 +400,7 @@ static int mt7621_pcie_parse_dt(struct mt7621_pcie *pcie)
err = of_pci_get_devfn(child);
if (err < 0) {
+ of_node_put(child);
dev_err(dev, "failed to parse devfn: %d\n", err);
return err;
}
@@ -407,8 +408,10 @@ static int mt7621_pcie_parse_dt(struct mt7621_pcie *pcie)
slot = PCI_SLOT(err);
err = mt7621_pcie_parse_port(pcie, child, slot);
- if (err)
+ if (err) {
+ of_node_put(child);
return err;
+ }
}
return 0;
--
2.19.1
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