> > There are two problems with this loop. 1) It unregisters the device > > which failed to register. 2) It is a forever loop. > > > > Even if "i" is a signed int? The infinite loop is because "i" is not decremented anywhere in the loop. Not because of signedness. Thanks, Manohar Vanga _______________________________________________ devel mailing list devel@xxxxxxxxxxxxxxxxxxxxxx http://driverdev.linuxdriverproject.org/mailman/listinfo/devel
