On 07/24/2013 03:09 AM, Tejun Heo wrote:
Hello,
On Fri, Jul 19, 2013 at 03:59:15PM +0800, Tang Chen wrote:
+#define MEMBLK_FLAGS_DEFAULT 0x0 /* default flag */
Please don't do this. Just clearing the struct as zero is enough.
@@ -439,12 +449,14 @@ repeat:
int __init_memblock memblock_add_node(phys_addr_t base, phys_addr_t size,
int nid)
{
- return memblock_add_region(&memblock.memory, base, size, nid);
+ return memblock_add_region(&memblock.memory, base, size,
+ nid, MEMBLK_FLAGS_DEFAULT);
And just use zero for no flag. Doing something like the above gets
weird with actual flags. e.g. if you add a flag, say, MEMBLK_HOTPLUG,
should it be MEMBLK_FLAGS_DEFAULT | MEMBLK_HOTPLUG or just
MEMBLK_HOTPLUG? If latter, the knowledge that DEFAULT is zero is
implicit, and, if so, why do it at all?
OK, will remove MEMBLK_FLAGS_DEFAULT, and use 0 by default.
+static int __init_memblock memblock_reserve_region(phys_addr_t base,
+ phys_addr_t size,
+ int nid,
+ unsigned long flags)
{
struct memblock_type *_rgn =&memblock.reserved;
- memblock_dbg("memblock_reserve: [%#016llx-%#016llx] %pF\n",
+ memblock_dbg("memblock_reserve: [%#016llx-%#016llx] with flags %#016lx %pF\n",
Let's please drop "with" and do we really need to print full 16
digits?
Sure, will remove "with". But I think printing out the full flags is batter.
The output seems more tidy.
Thanks.
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