On Wed, Feb 2, 2022 at 5:19 PM David Laight <David.Laight@xxxxxxxxxx> wrote: > > - The conditional operator (?:) requires that both expressions have the > the same type (after numeric promotions). I think you are referring to the arithmetic types case, but that one does not apply here. > - If the expressions have distinct non-NULL pointer types then they are both > cast to (void *) and the result has type 'void *'. GCC and Clang give `void *` for this, but something like `float *` and `int *` do not fit the constrains of the operator. Cheers, Miguel
