Re: [PATCH v16 2/5] random: add vgetrandom_alloc() syscall

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On Thu, May 30, 2024 at 08:59:17PM -0700, Eric Biggers wrote:
> On Tue, May 28, 2024 at 02:19:51PM +0200, Jason A. Donenfeld wrote:
> > +/**
> > + * sys_vgetrandom_alloc - Allocate opaque states for use with vDSO getrandom().
> > + *
> > + * @num:	   On input, a pointer to a suggested hint of how many states to
> > + * 		   allocate, and on return the number of states actually allocated.
> > + *
> > + * @size_per_each: On input, must be zero. On return, the size of each state allocated,
> > + * 		   so that the caller can split up the returned allocation into
> > + * 		   individual states.
> > + *
> > + * @addr:	   Reserved, must be zero.
> > + *
> > + * @flags:	   Reserved, must be zero.
> > + *
> > + * The getrandom() vDSO function in userspace requires an opaque state, which
> > + * this function allocates by mapping a certain number of special pages into
> > + * the calling process. It takes a hint as to the number of opaque states
> > + * desired, and provides the caller with the number of opaque states actually
> > + * allocated, the size of each one in bytes, and the address of the first
> > + * state, which may be split up into @num states of @size_per_each bytes each,
> > + * by adding @size_per_each to the returned first state @num times, while
> > + * ensuring that no single state straddles a page boundary.
> > + *
> > + * Returns the address of the first state in the allocation on success, or a
> > + * negative error value on failure.
> > + *
> > + * The returned address of the first state may be passed to munmap(2) with a
> > + * length of `(size_t)num * (size_t)size_per_each`, in order to deallocate the
> > + * memory, after which it is invalid to pass it to vDSO getrandom().
> 
> Wouldn't a munmap with '(size_t)num * (size_t)size_per_each' be potentially too
> short, due to how the allocation is sized such that states don't cross page
> boundaries?

You're right, I think. The calculation should instead be something like:

    DIV_ROUND_UP(num, PAGE_SIZE / size_per_each) * PAGE_SIZE

Does that seem correct to you?

Jason




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