The assignments to clear a through h and t1/t2 are optimized out by the compiler because they are unused after the assignments. These variables shouldn't be very sensitive: t1/t2 can be calculated from a through h, so they don't reveal any additional information. Knowing a through h is equivalent to knowing one 64-byte block's SHA256 hash (with non-standard initial value) which, assuming SHA256 is secure, doesn't reveal any information about the input. Signed-off-by: Arvind Sankar <nivedita@xxxxxxxxxxxx> --- lib/crypto/sha256.c | 1 - 1 file changed, 1 deletion(-) diff --git a/lib/crypto/sha256.c b/lib/crypto/sha256.c index d43bc39ab05e..099cd11f83c1 100644 --- a/lib/crypto/sha256.c +++ b/lib/crypto/sha256.c @@ -202,7 +202,6 @@ static void sha256_transform(u32 *state, const u8 *input) state[4] += e; state[5] += f; state[6] += g; state[7] += h; /* clear any sensitive info... */ - a = b = c = d = e = f = g = h = t1 = t2 = 0; memzero_explicit(W, 64 * sizeof(u32)); } -- 2.26.2
