<trimmed to: list due to being somewhat off-topic> > -----Original Message----- > From: Eric Biggers <ebiggers@xxxxxxxxxx> > Sent: Thursday, August 8, 2019 7:15 PM > To: Pascal Van Leeuwen <pvanleeuwen@xxxxxxxxxxxxxx> > Cc: Milan Broz <gmazyland@xxxxxxxxx>; Ard Biesheuvel <ard.biesheuvel@xxxxxxxxxx>; linux- > crypto@xxxxxxxxxxxxxxx; herbert@xxxxxxxxxxxxxxxxxxx; agk@xxxxxxxxxx; snitzer@xxxxxxxxxx; > dm-devel@xxxxxxxxxx > Subject: Re: [RFC PATCH v2] md/dm-crypt - reuse eboiv skcipher for IV generation > > On Thu, Aug 08, 2019 at 01:23:10PM +0000, Pascal Van Leeuwen wrote: > > > -----Original Message----- > > > From: Milan Broz <gmazyland@xxxxxxxxx> > > > Sent: Thursday, August 8, 2019 2:53 PM > > > To: Pascal Van Leeuwen <pvanleeuwen@xxxxxxxxxxxxxx>; Eric Biggers > <ebiggers@xxxxxxxxxx> > > > Cc: Ard Biesheuvel <ard.biesheuvel@xxxxxxxxxx>; linux-crypto@xxxxxxxxxxxxxxx; > > > herbert@xxxxxxxxxxxxxxxxxxx; agk@xxxxxxxxxx; snitzer@xxxxxxxxxx; dm-devel@xxxxxxxxxx > > > Subject: Re: [RFC PATCH v2] md/dm-crypt - reuse eboiv skcipher for IV generation > > > > > > On 08/08/2019 11:31, Pascal Van Leeuwen wrote: > > > >> -----Original Message----- > > > >> From: Eric Biggers <ebiggers@xxxxxxxxxx> > > > >> Sent: Thursday, August 8, 2019 10:31 AM > > > >> To: Pascal Van Leeuwen <pvanleeuwen@xxxxxxxxxxxxxx> > > > >> Cc: Ard Biesheuvel <ard.biesheuvel@xxxxxxxxxx>; linux-crypto@xxxxxxxxxxxxxxx; > > > >> herbert@xxxxxxxxxxxxxxxxxxx; agk@xxxxxxxxxx; snitzer@xxxxxxxxxx; dm- > devel@xxxxxxxxxx; > > > >> gmazyland@xxxxxxxxx > > > >> Subject: Re: [RFC PATCH v2] md/dm-crypt - reuse eboiv skcipher for IV generation > > > >> > > > >> On Wed, Aug 07, 2019 at 04:14:22PM +0000, Pascal Van Leeuwen wrote: > > > >>>>>> In your case, we are not dealing with known plaintext attacks, > > > >>>>>> > > > >>>>> Since this is XTS, which is used for disk encryption, I would argue > > > >>>>> we do! For the tweak encryption, the sector number is known plaintext, > > > >>>>> same as for EBOIV. Also, you may be able to control data being written > > > >>>>> to the disk encrypted, either directly or indirectly. > > > >>>>> OK, part of the data into the CTS encryption will be previous ciphertext, > > > >>>>> but that may be just 1 byte with the rest being the known plaintext. > > > >>>>> > > > >>>> > > > >>>> The tweak encryption uses a dedicated key, so leaking it does not have > > > >>>> the same impact as it does in the EBOIV case. > > > >>>> > > > >>> Well ... yes and no. The spec defines them as seperately controllable - > > > >>> deviating from the original XEX definition - but in most practicle use cases > > > >>> I've seen, the same key is used for both, as having 2 keys just increases > > > >>> key storage requirements and does not actually improve effective security > > > >>> (of the algorithm itself, implementation peculiarities like this one aside > > > >>> :-), as XEX has been proven secure using a single key. And the security > > > >>> proof for XTS actually builds on that while using 2 keys deviates from it. > > > >>> > > > >> > > > >> This is a common misconception. Actually, XTS needs 2 distinct keys to be a > > > >> CCA-secure tweakable block cipher, due to another subtle difference from XEX: > > > >> XEX (by which I really mean "XEX[E,2]") builds the sequence of masks starting > > > >> with x^1, while XTS starts with x^0. If only 1 key is used, the inclusion of > > > >> the 0th power in XTS allows the attack described in Section 6 of the XEX paper > > > >> (https://web.cs.ucdavis.edu/~rogaway/papers/offsets.pdf). > > > >> > > > > Interesting ... I'm not a cryptographer, just a humble HW engineer specialized > > > > in implementing crypto. I'm basing my views mostly on the Liskov/Minematsu > > > > "Comments on XTS", who assert that using 2 keys in XTS was misguided. > > > > (and I never saw any follow-on comments asserting that this view was wrong ...) > > > > On not avoiding j=0 in the XTS spec they actually comment: > > > > "This difference is significant in security, but has no impact on effectiveness > > > > for practical applications.", which I read as "not relevant for normal use". > > See page 6 of "Comments on XTS": > > Note that j = 0 must be excluded, as f(0, v) = v for any v, which > implies ρ = 1. Moreover, if j = 0 was allowed, a simple attack based on > this fact existed, as pointed out by [6] and [3]. Hence if XEX is used, > one must be careful to avoid j being 0. > Ok, I missed that part. Something to do with being surrounded by far too much math :-P I did figure out by myself that forcing the ciphertext to 0 for the first block and being able to observe the plaintext coming out would give you S ^ E(S) if both keys are equal due do D(0 ^ E(x)) being x. I guess that's the f(0,v) = v in the above. Which would give you E(S) as S is usually known. (But this doesn't have to be the case! S *can* be made a secret within the XTS specification!) Which in turn would give you all tweaks E(S) * alpha(j), reducing the encryption /for that sector only/ to just basic ECB. Still, that does not constitute a full attack on the sector at hand (which is not so relevant, since it was leaking plaintext, so you can assume it does not contain any sensitive data!), let alone any other sector on the disk or even the key. At least, I have not seen that demonstrated yet. So it may be bad in the general cryptographic sense, but I still doubt it has very significant practicle implications if you assume the system is not leaking any plaintext from any sensitive areas of the disk. Still, FIPS seems to consider it a risk so who am I to doubt that ;-) > The part you quoted is only talking about XTS *as specified*, i.e. with 2 keys. > Ok, that makes sense actually. Would have been better if they mentioned that that statement only only holds if the keys are not equal ... (which, BTW, is not a requirement mentioned anywhere in the XTS specification) > > > > > > > > In any case, it's frequently *used* with both keys being equal for performance > > > > and key storage reasons. > > It's broken, so it's broken. Doesn't matter who is using it. > Well, it does kind of matter for people that still want to read their disk - and possibly continue to use it - encrypted with the "broken" version :-) And "broken" is a relative term anyway. As long as you can't get to the key, decrypt random sectors or manipulate random bits, it may be secure enough for its purpose. > > > > > > There is already check in kernel for XTS "weak" keys (tweak and encryption keys must > not be > > > the same). > > > > > > > https://git.kernel.org/pub/scm/linux/kernel/git/torvalds/linux.git/tree/include/crypto/xts > .h# > > > n27 > > > > > > For now it applies only in FIPS mode... (and if I see correctly it is duplicated in > all > > > drivers). > > > > > I never had any need to look into FIPS for XTS before, but this actually appears > > to be accurate. FIPS indeed *requires this*. Much to my surprise, I might add. > > Still looking for some actual rationale that goes beyond suggestion and innuendo > > (and is not too heavy on the math ;-) though. > > As I said, the attack is explained in the original XEX paper. Basically the > adversary can submit a chosen ciphertext query for the first block of sector 0 > to leak the first "mask" of that sector, then submit a chosen plaintext or > ciphertext query for the reminder of the sector such that they can predict the > output with 100% certainty. (The standard security model for tweakable block > ciphers says the output must appear random.) > Yes, but that only affects a sector that was leaking plaintext to begin with. I'm not impressed until you either recover the key or can decrypt or manipulate *other* sectors on the disk. > - Eric Regards, Pascal van Leeuwen Silicon IP Architect, Multi-Protocol Engines @ Verimatrix www.insidesecure.com
