Hi, I'm trying to understand the code for AES encryption from ARM-CE. >From the aes-glue.S calls I understand that the encryption primitives receive the number of blocks, but have no way of determining the number of bytes to encrypt, if for example the plaintext does not have a length of a multiple of AES block size. How does, for example, ecb_encrypt() also encrypt the last remaining bytes in the plaintext if it is not a multiple of AES block size if It can never deduce the full plaintext size? Catalin Vasile-- To unsubscribe from this list: send the line "unsubscribe linux-crypto" in the body of a message to majordomo@xxxxxxxxxxxxxxx More majordomo info at http://vger.kernel.org/majordomo-info.html
