Am Donnerstag, 23. April 2015, 09:39:28 schrieb Herbert Xu: Hi Herbert, > On Wed, Apr 22, 2015 at 02:44:08PM +0200, Stephan Mueller wrote: > > > Where does this 8-byte alignment requirement come from? > > > > Well, I am accessing the data in 8-byte chunks. Moreover, in the > > scatterwalk copy functions, I search through the scatterlists in 8 byte > > increments. If, say, a scatterwalk is not a multiple of 8 bytes, the > > scatterwalk logic will not process the last chunk of memory. > > Alignment refers to whether the address can handle a load of a > given size by the CPU, it does not mean that the length will > be a multiple of the alignment. Alignment is only required if > you do a load of the given size. > > For example if you read a u64 then on many architectures that > will require an alignment of 8. Vice versa if you only do byte > loads then you do not need to specify the alignment. > > I don't see any u64 loads in your code. Ok, I will remove it. > > Cheers, -- Ciao Stephan -- To unsubscribe from this list: send the line "unsubscribe linux-crypto" in the body of a message to majordomo@xxxxxxxxxxxxxxx More majordomo info at http://vger.kernel.org/majordomo-info.html
