On Thu, Jul 17, 2014 at 01:27:06PM -0700, Andy Lutomirski wrote: > > + return urandom_read(NULL, buf, count, NULL); > > This can return -ERESTARTSYS. Does it need any logic to restart correctly? Nope; because we only return -ERESTARTSYS when we haven't generated any randomness yet. The way /dev/urandom and /dev/random devices work is that if we get interrupted, we return a short read. We do *not* resume generation of random bytes from where we got interrupted from the signal handler. This is consistent with the definition in the signal(7) man page: If a blocked call to one of the following interfaces is interrupted by a signal handler, then the call will be automatically restarted after the signal handler returns if the SA_RESTART flag was used; otherwise the call will fail with the error EINTR: * read(2), readv(2), write(2), writev(2), and ioctl(2) calls on "slow" devices. A "slow" device is one where the I/O call may block for an indefinite time, for example, a terminal, pipe, or socket. (A disk is not a slow device according to this definition.) If an I/O call on a slow device has already transferred some data by the time it is interrupted by a signal handler, then the call will return a success status (normally, the number of bytes transferred). And in answer to Zach's question along these lines, ERESTARTSYS gets restarted or transformed into EINTR by the system call layer, so long as you only set ERESTARTSYS when signal_pending(current) is true. If you accidentally set the return value to ERESTARTSYS when a signal is not pending, this error code can escape out to user space, which is considered a bug. But we're using this correctly in drivers/char/random.c. - Ted -- To unsubscribe from this list: send the line "unsubscribe linux-crypto" in the body of a message to majordomo@xxxxxxxxxxxxxxx More majordomo info at http://vger.kernel.org/majordomo-info.html