Hi Oleg,
Oleg Nesterov (oleg@xxxxxxxxxx) wrote:
> Hi Mandeep,
>
> On 01/11, Mandeep Singh Baines wrote:
> > > >
> > > > #define while_each_thread(g, t, o) \
> > > > while (t->group_leader == o && (t = next_thread(t)) != g)
> > > >
> > > > Where o should have the value of g->group_leader.
> > >
> > > I don't understand how this helps... and how this can work even
> > > ignoring the barriers.
> > >
> > > OK, we have the main thream M and the sub-thread T, we are doing
> > >
> > > do {
> > > do_something(t);
> > > } while_each_thread(M, t, M);
> > >
> > > why we can't miss T if it does exec?
> > >
> >
> > So for:
> >
> > struct task *M; /* assuming this is passed in to us */
> > struct task *L = M->group_leader;
>
> L == M
>
> > do {
> > do_something(T);
> > } while_each_thread(M, T, L);
> >
> > Here is my thinking.
> >
> > If some thread K does exec, you won't miss it because:
> >
> > 1) Ignoring the group_leader check, you'll visit K just by following
> > next_thread(). That's the case today and is what you except
> > when iterating over an rcu_list.
> > 2) (t->group_leader == o) will fail iff t is the exec thread.
> > Since we test t->group_leader before re-assigning it (t=next_thread()),
> > the test will fail only after visiting the exec thread. So you'll
> > visit the exec thread and then terminate the loop.
>
> Still can't understand... Lets look at this trivial example again.
>
> We start from the main thread M, it is ->group_leader. There is
> another thread T in this thread group. We are doing
>
> OLD = M;
>
> t = M;
> do {
> do_smth(t);
> }
> while (t->group_leader == OLD && ((t = next_thread(t)) != M);
>
> The first iteration does do_smth(M).
>
> T calls de_thread() and, in particular, it does M->group_leader = T
> (see "leader->group_leader = tsk" in de_thread).
>
> after that t->group_leader == OLD fails. t == M, its group_leader == T.
> do_smth(T) won't be called.
>
> No?
>
I think we can handle this by removing the assignment. So in de_thread():
- leader->group_leader = tsk;
tsk->exit_signal = SIGCHLD;
leader->exit_signal = -1;
BUG_ON(leader->exit_state != EXIT_ZOMBIE);
leader->exit_state = EXIT_DEAD;
In the current d_thread(), four statements after reassigning
leader->group_leader, we mark the old leader as EXIT_DEAD. So what if
we leave leader->group_leader = leader. Since its EXIT_DEAD a few
statements later, I don't think anything should break.
What do you think?
Regards,
Mandeep
> Oleg.
>
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