Hi everybody! Suppose that I have 3 shared files, and two target machines M1 and M2. libA.so, libB.so and libC.so. libB.so is linked against libA.so only when compiled to M1, but not in M2. libC.so is aways linked against libB.so So we have: M1: libA.so <- libB.so <- libC.so <- executable. M2: libB.so <- libC.so <-executable I want to hide libA.so need while linking libB, so that libC has not to pass -lA to linker depending on machine. And to hide libB and libA while linking to libC, so that the user need to pass only -lC. Is that possible? For example, linking in M1 would be: cc -fPIC -shared -o libA.so libA.c cc -fPIC -shared -o libB.so libB.c -lA cc -fPIC -shared -o libC.so libC.c -lB (no need to -lA is the point here) cc -o executable executable.c -lC (no need to -lB -lA is the point here) And for M2 would be: cc -fPIC -shared -o libB.so libB.c cc -fPIC -shared -o libC.so -lB cc -o executable executable.c -lC In both cases (machines) the compilation of executable and libC is done by the same command line. Cheers, -- "Do or do not. There is no try" Yoda Master -- To unsubscribe from this list: send the line "unsubscribe linux-c-programming" in the body of a message to majordomo@xxxxxxxxxxxxxxx More majordomo info at http://vger.kernel.org/majordomo-info.html
