1) a .* xptr = 3 ;
Above line's syntax is wrong.
Should be
*a.xptr = 3;
2) Also declare the structure member variables as
int *xptr, *yptr ; (otherwise yptr will be of type int, not of int*)
3) aptr ->* xptr = 5 ;
is also of wrong syntax.
Should be
*aptr->xptr = 5 ;
Which is equivalent to
*(aptr->xptr) = 5;
the above code DOES NOT mean this one :
(*aptr)->xptr // this one dereference aptr first, then
does nothing to xptr
Thanks.
On Tue, Aug 2, 2011 at 10:01 PM, Shriramana Sharma <samjnaa@xxxxxxxxx> wrote:
>
> Hello -- long time since I posted on this list.
>
> I'm trying to understand the use of ->* but in compiling the attached program which I thought was straightforward I am getting the following errors:
>
> foo.cpp: In constructor ‘mystruct::mystruct()’:
> foo.cpp:9:12: error: invalid conversion from ‘int*’ to ‘int’
> foo.cpp: In function ‘int main()’:
> foo.cpp:21:7: error: ‘xptr’ was not declared in this scope
> foo.cpp:22:7: error: ‘yptr’ was not declared in this scope
>
> Please help.
>
> --
> Shriramana Sharma
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