simon wrote: > char (*pa())[4]; > is this mean that an pa function pointer with return value like a char a[4] and it's argument is nothing ? > > right? Wrong. 1. pa is not a pointer to a function, it's a function which returns a pointer. "()" has higher precedence than "*", so "*pa()" is parsed as "*(pa())" (function returning pointer) rather than "(*pa)()" (pointer to function). 2. An empty parameter list "()" indicates that the function takes unspecified arguments. A function which takes no arguments has "(void)" as the parameter list. -- Glynn Clements <glynn@xxxxxxxxxxxxxxxxxx> -- To unsubscribe from this list: send the line "unsubscribe linux-c-programming" in the body of a message to majordomo@xxxxxxxxxxxxxxx More majordomo info at http://vger.kernel.org/majordomo-info.html
