Hi guys of dear forum!I am a new programmer in C programming language and i
have a question for you about the following C code:
#include <stdio.h>
#include <stdlib.h>
int main()
{
int x;
int answer;
int right;
int wrong;
printf("This is a program of sum\n");
right = 0; /*Initialization of right value*/
wrong = 0; /*Initialization of wrong value*/
for(x = 1; x <= 10; x++)[QUOTE][/QUOTE]
{
printf("What is %d + %d: ", x, x);
scanf("%d", &answer);
printf("The sum is %d\n", answer);
printf("\a");
if(answer == x + x)
{
printf("%d is RIGHT answer\n", answer);
right++; /*Saves and increases the amount of right answers*/
}
else
{
printf("%d is WRONG answer\n", answer);
b[10] = answer;
wrong++; /*Saves and increases the amount of wrong answers*/
printf("The correct answer is %d\n", x + x);
}
}
printf("The right answers are %d and the wrong are %d\n", right, wrong);
fflush(stdin);
getchar();
}
First, I use DEV C++ compiler!This program asks from user to find the sum of
1+1,2+2 until for loop reaches 10.As you can observe with right++ and
wrong++ i can define and print to the screen the amount of right or wrong
numbers!
My question is how could I define the number of correct and wrong numbers in
collaboration with their amount?For example:
The right answers are 8 and wrong are 2
The right answers are 2 4 6 8 10 12 14 16
The wrong answers are 22 44
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