Say 16 bit compiler (for ex Turbo C) uses 2's compliment to find the range of signed integer. Say for 16 bit n=16. Now applying 2's compliment equation : -2^(n-1) to 2^(n-1) -1 so for n=16 : The range is -32768 to 32767 This is ok. The question arises when it tell about real constant's range. For 16 bit compiler the range of real constant is : -3.4e38 to 3.4e38 How they arrived to this real constant range? Can any one share the mathematical calculation behind it? thnx, RAM_LOCK -- View this message in context: http://www.nabble.com/how-compiler-decide-the-range-of-real-numbers-in-C...-tp24743191p24743191.html Sent from the linux-c-programming mailing list archive at Nabble.com. -- To unsubscribe from this list: send the line "unsubscribe linux-c-programming" in the body of a message to majordomo@xxxxxxxxxxxxxxx More majordomo info at http://vger.kernel.org/majordomo-info.html
