it's offset address and not absolute address.
base addresses of your parent and child process will be different so
final absolute address (base + offset) will be different for both.
beginner_h4x3r wrote:
Hi All..
I am a beginner hacker, i want to learn Linux from scratch. I read
some resources on Linux's process management. Process duplicates it's
page table to it's child process, right? so i wrote demonstrate code
to prove this.
#include <stdio.h>
#include <stdlib.h>
#include <unistd.h>
#include <sys/types.h>
#include <sys/wait.h>
int main (void) {
pid_t child;
int stack_int;
child = fork ();
if (child == 0) {
sleep (1); /* ;p */
printf ("child process stack_int value %i, address: %p\n",
stack_int, &stack_int);
exit (0);
}
if (child == -1) {
perror ("fork");
return -1;
}
stack_int = 32;
printf ("main process stack_int value %i, address: %p\n", stack_int,
&stack_int);
waitpid (child, NULL, 0);
return 0;
}
The output is:
main process stack_int value 32, address: 0xbf9c66ec
child process stack_int value 8495092, address: 0xbf9c66ec
stack_int value is different from parent and it's child.
My question: why the stack_int has a same address between parent and
it's child ?, but confusedly... they have a different value, i was
though it should be different, since process duplicate it's page to
child, please explain me. ;)
Thanks before.
--- curious_hacker
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