Hi Marcel!
Sorry sorry!! This is obviously not necessary!
This is code that was left when I tried to split up my original big patch.
This was part of code trying to solve a possible divided by 0.
int q = 0;
...
if (num)
q = cnt / num;
*quote = q ? q : 1;
But I'm not sure if it can happen in reality...
Guessing it will be caught by in that case by:
if (!chan)
return NULL;
I had actually not planned to submit this divided by 0 patch at all :-/
Best regards
Rickard Strandqvist
2014-06-01 16:24 GMT+02:00 Marcel Holtmann <marcel@xxxxxxxxxxxx>:
> Hi Rickard,
>
>> There is a risk that the variable will be used without being initialized.
>>
>> This was largely found by using a static code analysis program called cppcheck.
>>
>> Signed-off-by: Rickard Strandqvist <rickard_strandqvist@xxxxxxxxxxxxxxxxxx>
>> ---
>> net/bluetooth/hci_core.c | 2 +-
>> 1 file changed, 1 insertion(+), 1 deletion(-)
>>
>> diff --git a/net/bluetooth/hci_core.c b/net/bluetooth/hci_core.c
>> index 1c6ffaa..1d93d2f 100644
>> --- a/net/bluetooth/hci_core.c
>> +++ b/net/bluetooth/hci_core.c
>> @@ -4603,7 +4603,7 @@ static struct hci_chan *hci_chan_sent(struct hci_dev *hdev, __u8 type,
>> struct hci_chan *chan = NULL;
>> unsigned int num = 0, min = ~0, cur_prio = 0;
>> struct hci_conn *conn;
>> - int cnt, q, conn_num = 0;
>> + int cnt, q = 0, conn_num = 0;
>
> I have no idea on how the variable will be used without being initialized. Have you actually looked through that function. The only thing we do with q is assign it and then use it. That is it.
>
> Regards
>
> Marcel
>
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