From: Li Nan <linan122@xxxxxxxxxx>
badblocks will loss if we set it as below:
# echo 1 1 > bad_blocks
# echo 3 1 > bad_blocks
# echo 1 5 > bad_blocks
# cat bad_blocks
1 3
In badblocks_set(), if there is an intersection between p[lo] and p[hi],
we will combine them. The end of new badblocks is p[hi]'s end now. but
p[lo] may cross p[hi] and new end should be the larger of p[lo] and p[hi].
Fixes: 9e0e252a048b ("badblocks: Add core badblock management code")
Signed-off-by: Li Nan <linan122@xxxxxxxxxx>
---
block/badblocks.c | 10 ++++------
1 file changed, 4 insertions(+), 6 deletions(-)
diff --git a/block/badblocks.c b/block/badblocks.c
index 7e6ebe2ac12c..2c2ef8284a3f 100644
--- a/block/badblocks.c
+++ b/block/badblocks.c
@@ -267,16 +267,14 @@ int badblocks_set(struct badblocks *bb, sector_t s, int sectors,
if (sectors == 0 && hi < bb->count) {
/* we might be able to combine lo and hi */
/* Note: 's' is at the end of 'lo' */
- sector_t a = BB_OFFSET(p[hi]);
- int lolen = BB_LEN(p[lo]);
- int hilen = BB_LEN(p[hi]);
- int newlen = lolen + hilen - (s - a);
+ sector_t a = BB_OFFSET(p[lo]);
+ int newlen = max(s, BB_OFFSET(p[hi]) + BB_LEN(p[hi])) - a;
- if (s >= a && newlen < BB_MAX_LEN) {
+ if (s >= BB_OFFSET(p[hi]) && newlen < BB_MAX_LEN) {
/* yes, we can combine them */
int ack = BB_ACK(p[lo]) && BB_ACK(p[hi]);
- p[lo] = BB_MAKE(BB_OFFSET(p[lo]), newlen, ack);
+ p[lo] = BB_MAKE(a, newlen, ack);
memmove(p + hi, p + hi + 1,
(bb->count - hi - 1) * 8);
bb->count--;
--
2.31.1
