From: Joe Perches
> Sent: 22 February 2022 18:43
>
> On Tue, 2022-02-22 at 08:56 -0800, Keith Busch wrote:
> > On Tue, Feb 22, 2022 at 05:50:45PM +0100, Christoph Hellwig wrote:
> > > On Tue, Feb 22, 2022 at 08:45:53AM -0800, Joe Perches wrote:
> > > > On Tue, 2022-02-22 at 08:31 -0800, Keith Busch wrote:
> > > > > +/ *
> > > > > + * lower_48_bits - return bits 0-47 of a number
> > > > > + * @n: the number we're accessing
> > > > > + */
> > > > > +#define lower_48_bits(n) ((u64)((n) & 0xffffffffffffull))
> > > >
> > > > why not make this a static inline function?
> > >
> > > Agreed.
> >
> > Sure, that sounds good to me. I only did it this way to match the
> > existing local convention, but I personally prefer the inline function
> > too.
>
> The existing convention is used there to allow the compiler to
> avoid warnings and unnecessary conversions of a u32 to a u64 when
> shifting by 32 or more bits.
>
> If it's possible to be used with an architecture dependent typedef
> like dma_addr_t, then perhaps it's reasonable to do something like:
>
> #define lower_48_bits(val) \
> ({ \
> typeof(val) high = lower_16_bits(upper_32_bits(val)); \
> typeof(val) low = lower_32_bits(val); \
> \
> (high << 16 << 16) | low; \
> })
>
> and have the compiler have the return value be an appropriate type.
The compiler could make a real pigs breakfast of that.
For lower_46_bits() an integer promotion to u64 does no harm.
But for some other cases you get in a right mess when values
that should be unsigned get sign extended.
Although I think:
(val) & (((typeof(val))1 << 48) - 1)
avoids any promotion if anyone tries lower_48_bits(int_var).
(It is even likely to be a compile error.)
Oh, did you look for GENMASK([^,]*,[ 0]*) ?
I'd only use something GENMASK() for bit ranges.
Even then it is often easier to just write the value in hex.
I think the only time I've written anything like that recently
(last 30 years) was for some hardware registers when the documentation
user 'bit 1' for the most significant bit.
It's rather like I just know that (x & (x - 1)) checks for 1 bit being set.
I have to lookup is_power_of_2() to see what it does.
David
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