On Tue, Feb 04, 2020 at 11:37:11AM -0800, Salman Qazi wrote:
> Flushes bypass the I/O scheduler and get added to hctx->dispatch
> in blk_mq_sched_bypass_insert. This can happen while a kworker is running
> hctx->run_work work item and is past the point in
> blk_mq_sched_dispatch_requests where hctx->dispatch is checked.
>
> The blk_mq_do_dispatch_sched call is not guaranteed to end in bounded time,
> because the I/O scheduler can feed an arbitrary number of commands.
>
> Since we have only one hctx->run_work, the commands waiting in
> hctx->dispatch will wait an arbitrary length of time for run_work to be
> rerun.
>
> A similar phenomenon exists with dispatches from the software queue.
>
> The solution is to poll hctx->dispatch in blk_mq_do_dispatch_sched and
> blk_mq_do_dispatch_ctx and return from the run_work handler and let it
> rerun.
>
> Signed-off-by: Salman Qazi <sqazi@xxxxxxxxxx>
> ---
> block/blk-mq-sched.c | 6 ++++++
> 1 file changed, 6 insertions(+)
>
> diff --git a/block/blk-mq-sched.c b/block/blk-mq-sched.c
> index ca22afd47b3d..d1b8b31bc3d4 100644
> --- a/block/blk-mq-sched.c
> +++ b/block/blk-mq-sched.c
> @@ -97,6 +97,9 @@ static void blk_mq_do_dispatch_sched(struct blk_mq_hw_ctx *hctx)
> if (e->type->ops.has_work && !e->type->ops.has_work(hctx))
> break;
>
> + if (!list_empty_careful(&hctx->dispatch))
> + break;
> +
> if (!blk_mq_get_dispatch_budget(hctx))
> break;
>
> @@ -140,6 +143,9 @@ static void blk_mq_do_dispatch_ctx(struct blk_mq_hw_ctx *hctx)
> do {
> struct request *rq;
>
> + if (!list_empty_careful(&hctx->dispatch))
> + break;
> +
> if (!sbitmap_any_bit_set(&hctx->ctx_map))
> break;
This approach looks good, given actually we retrieved request this way in
legacy IO request path, see __elv_next_request().
However, blk_mq_request_bypass_insert() may be run at the same time, so
this patch may cause requests stalled in scheduler queue.
How about returning if there is request available in hctx->dispatch from
the two helpers, then re-dispatch requests in blk_mq_sched_dispatch_requests()
if yes.
Thanks,
Ming
