From: Tang Junhui <tang.junhui@xxxxxxxxxx>
>>
>> More importantly,
>>> + while (!kthread_should_stop() && next) {
>>> ...
>>> + if (nk != 0 && !keys_contiguous(dc, keys[nk-1], next))
>>> + break;
>>> +
>>> + size += KEY_SIZE(&next->key);
>>> + keys[nk++] = next;
>>> + } while ((next = bch_keybuf_next(&dc->writeback_keys)));
>>
>> if the "next" key does not satisfy the contiguous condition, does this
>> key not write-back to the backend device?
>
>I believe the current code is correct--- it is not written back *this
>time* (since it is not contiguous), but will be written back the next
>time through the loop (next is not changed).
>
Oh, yes, that's right. I read the wrong while{} loop.
Thanks,
Tang
