Re: [PATCH] block: iocost: ensure hweight_inuse is at least 1

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Hi,

在 2024/11/22 15:26, Kunhai Dai 写道:
The hweight_inuse calculation in transfer_surpluses() could potentially
result in a value of 0, which would lead to division by zero errors in
subsequent calculations that use this value as a divisor.

Signed-off-by: Kunhai Dai <daikunhai@xxxxxxxxxxxxxx>
---
  block/blk-iocost.c | 7 ++++---
  1 file changed, 4 insertions(+), 3 deletions(-)

diff --git a/block/blk-iocost.c b/block/blk-iocost.c
index 384aa15e8260..65cdb55d30cc 100644
--- a/block/blk-iocost.c
+++ b/block/blk-iocost.c
@@ -1999,9 +1999,10 @@ static void transfer_surpluses(struct list_head *surpluses, struct ioc_now *now)
  		parent = iocg->ancestors[iocg->level - 1];
/* b' = gamma * b_f + b_t' */
-		iocg->hweight_inuse = DIV64_U64_ROUND_UP(
-			(u64)gamma * (iocg->hweight_active - iocg->hweight_donating),
-			WEIGHT_ONE) + iocg->hweight_after_donation;
+		iocg->hweight_inuse = max_t(u64, 1,
+			DIV64_U64_ROUND_UP(
+				(u64)gamma * (iocg->hweight_active - iocg->hweight_donating),
+				WEIGHT_ONE) + iocg->hweight_after_donation);

I'm confused, how could DIV64_U64_Round_UP() end up less than 1?

#define DIV64_U64_ROUND_UP(ll, d)       \
        ({ u64 _tmp = (d); div64_u64((ll) + _tmp - 1, _tmp); })

AFAIK, the only case that could happen is that
iocg->hweight_active - iocg->hweight_donating is 0, then I don't
get it now how cound active iocg donate all the hweight, if this
really happend perhaps the better solution is to avoid such case.

Thanks,
Kuai

/* w' = s' * b' / b'_p */
  		inuse = DIV64_U64_ROUND_UP(






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