On 8/28/23 19:11, Shinichiro Kawasaki wrote:
This is the unclear point for me. Does bash really pass the arguments list of
the caller to the callee when functions are called without arguments?
Looking back the commit 852996fea4f1, you explained that bash does, and I
agreed. But now in my environment bash doesn't. I tried the script below in my
environment, and see nothing printed.
funcA() { echo "$1" ; }
funcB() { funcA; }
funcB foo
Then the arguments of funcB is not passed to funcA. How does it run in your
environment?
I see the same result that you see. It seems that I misinterpret the
text produced by shellcheck if it reports warning SC2119. After having
reread https://github.com/koalaman/shellcheck/wiki/SC2119, I'm OK with
suppressing warning SC2119 because that warning doesn't seem useful to
me.
Thanks,
Bart.
