Re: [dm-devel] [RFC] block: fix blk_queue_split() resource exhaustion

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On Fri, Jul 08 2016, Lars Ellenberg wrote:

> On Fri, Jul 08, 2016 at 08:07:52AM +1000, NeilBrown wrote:
>> Before I introduced the recursion limiting, requests were handled as an
>> in-order tree walk.  The code I wrote tried to preserve that but didn't
>> for several reasons.  I think we need to restore the original in-order
>> walk because it makes the most sense.
>> So after processing a particular bio, we should then process all the
>> 'child' bios - bios send to underlying devices.  Then the 'sibling'
>> bios, that were split off, and then any remaining parents and ancestors.
>> 
>> You patch created the right structures for doing this, my proposal took
>> it a step closer, but now after more careful analysis I don't think it
>> is quite right.
>> With my previous proposal (and you latest patch - thanks!) requests for
>> "this" level are stacked, but they should be queued.
>> If a make_request_fn only ever submits one request for this level and
>> zero or more lower levels, then the difference between a queue and a
>> stack is irrelevant.  If it submited more that one, a stack would cause
>> them to be handled in the reverse order.
>
> We have a device stack.
> q_this_level->make_request_fn() cannot possibly submit anything
> on "this_level", or it would create a device loop, I think.
>
> So we start with the initial, "top most" call to generic_make_request().
> That is one single bio. All queues are empty.
>
> This bio is then passed on to its destination queue make_request_fn().
>
> Which may chose to split it (via blk_queue_split, or like dm does, or
> else). If it, like blk_queue_split() does, splits it into
> "piece-I-can-handle-now" and "remainder", both still targeted at the
> top most (current) queue, I think the "remainder" should just be pushed
> back, which will make it look as if upper layers did
> 	generic_make_request("piece-I-can-handle-now");
> 	generic_make_request("remainder");
> Which I do, by using bio_list_add_head(remainder, bio); (*head*).

This is exactly what I mean by "submitting a request at 'this' level".
Maybe that is a poor way to express it.  Within a make_request_fn, you
cannot "submit" a request, you can only "queue" a request.
generic_make_request hides that by doing something different for a call
From a make_request_fn that for a call from anywhere else.
The important thing is to have 2 queues to queue to.

>
> I don't see any other way for a make_request_fn(bio(l=x)) to generate
> "sibling" bios to the same level (l=x) as its own argument.

Yes, it only comes from splitting.

>
> This same q(l=x)->make_request_fn(bio(l=x)) may now call
> generic_make_request() for zero or more "child" bios (l=x+1),
> which are queued in order: bio_list_add(recursion, bio); (*tail*).
> Then, once l=x returns, the queue generated by it is spliced
> in front of the "remainder" (*head*).
> All bios are processed in the order they have been queued,
> by peeling off of the head.
>
> After all "child" bios of level l>=x+1 have been processed,
> the next bio to be processed will be the "pushed back" remainder.
>
> All "Natural order".
>
>> To make the patch "perfect", and maybe even more elegant we could treat
>> ->remainder and ->recursion more alike.
>> i.e.:
>>   - generic make request has a private "stack" of requests.
>>   - before calling ->make_request_fn(), both ->remainder and ->recursion
>>     are initialised
>>   - after ->make_request_fn(), ->remainder are spliced in to top of
>>     'stack', then ->recursion is spliced onto that.
>>   - If stack is not empty, the top request is popped and we loop to top.
>> 
>> This reliably follows in-order execution, and handles siblings correctly
>> (in submitted order) if/when a request splits off multiple siblings.
>
> The only splitting that creates siblings on the current level
> is blk_queue_split(), which splits the current bio into
> "front piece" and "remainder", already processed in this order.

Yes.
I imagine that a driver *could* split a bio into three parts with a
single allocation, but I cannot actually see any point in doing it.  So
I was over-complicating things.

>
> Anything else creating "siblings" is not creating siblings for the
> current layer, but for the next deeper layer, which are queue on
> "recursion" and also processed in the order they have been generated.
>
>> I think that as long a requests are submitted in the order they are
>> created at each level there is no reason to expect performance
>> regressions.
>> All we are doing is changing the ordering between requests generated at
>> different levels, and I think we are restoring a more natural order.
>
> I believe both patches combined are doing exactly this already.
> I could rename .remainder to .todo or .incoming, though.

:-)  neither "remainder" or "recursion" seem like brilliant names to me,
but I don't have anything better to suggest.  Naming is hard!
As long as a comment explains the name clearly I could cope with X and Y.

>
> .incoming = [ bio(l=0) ]
> .recursion = []
>
> split
>
> .incoming = [ bio(l=0,now_1), bio(l=0,remainder_1) ]
> .recursion = []
>
> process head of .incoming
>
> .incoming = [ bio(l=0,remainder_1) ]
> .recursion = [ bio(l=1,a), bio(l=1,b), bio(l=1,c), ... ]
>
> merge_head
>
> .incoming = [ bio(l=1,a), bio(l=1,b), bio(l=1,c), ...,
> 		bio(l=0,remainder_1) ]
> .recursion = []
>
> process head of .incoming, potentially split first
>
> .incoming = [ bio(l=1,a,now), bio(l=1,a,remainder), bio(l=1,b), bio(l=1,c), ...,
> 		bio(l=0,remainder_1) ]
> ...
> .incoming = [ bio(l=1,a,remainder), bio(l=1,b), bio(l=1,c), ...,
> 		bio(l=0,remainder_1) ]
> .recursion = [ bio(l=2,aa), bio(l=2,ab), ... ]
>
> merge_head
>
> .incoming = [ bio(l=2,aa), bio(l=2,ab), ...,
> 		bio(l=1,a,remainder), bio(l=1,b), bio(l=1,c), ...,
> 		bio(l=0,remainder_1) ]
> .recursion = []
>
> ...
>
> process away ... until back at l=0
>
> .incoming = [ bio(l=0,remainder_1) ]
> .recursion = []
>
> potentially split further
> .incoming = [ bio(l=0,now_2), bio(l=0,remainder_2) ]
> .recursion = []
>
> rinse, repeat.

I think we just might be in violent agreement.

Thanks,
NeilBrown

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