Le 28 mars 2011 à 10:53, Cedric Roux a écrit :
>
> ----- "Julien Claassen" <julien@xxxxxxxx> wrote:
>
>> Hello Cedric!
>> I just changed it to int volatile done = 0 and added some debugging
>> output.
>> It jumps into the connecting branch (if(connect) ), then there's
>> the
>> expression:
>> if (jack_connect(client, jack_port_name(src_port),...
>> There it fails (i.e., it doesn't execute the following goto exit.
>> Instead,
>> it executed my prepare else and then hung around the while-loop
>> forever. Well,
>> I didn't wait that long. :-)
>> So any thoughts on that?
>> Warmly yours
>> Julien
>
> Julien,
>
> add the lines:
> /* tell the JACK server that we are ready to roll */
> if (jack_activate (client)) {
> fprintf (stderr, "cannot activate client");
> goto exit;
> }
>
> just before the lines:
> /* connect the ports. Note: you can't do this before
> the client is activated (this may change in the future).
> */
>
> if (connecting) {
>
> and add:
> jack_deactivate (client);
>
> just after the lines:
> // Wait for connection/disconnection to be effective
> while(!done) {
> #ifdef WIN32
> Sleep(10);
> #else
> usleep(10000);
> #endif
> }
>
> that does the trick for me.
>
> You should keep the "volatile" stuff. Without it the program
> may loop forever if compiled with gcc and some optimization.
>
> Note: it is normal that it doesn't jump to exit. Go read the
> sources of jack-1.9.6, it's clearer. It jumps to exit in case
> of error. It should do the while(!done) if things are alright.
OK commited those changes in JACK2 SVN 4223
Stéphane
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