On Sat, 2011-01-29 at 13:22 +0100, Philipp Ãberbacher wrote: > Without optimisation the output is quite > different, but beginning with -O2 the machine code appears all the same. That's because your 2048 is static, and nothing is happening in the loop, therefore gcc can optimise way more stuff away than in the real code, because it "knows" that buffer size is always 2048 and that k is not used inside the loop. Peter. _______________________________________________ Linux-audio-user mailing list Linux-audio-user@xxxxxxxxxxxxxxxxxxxx http://lists.linuxaudio.org/listinfo/linux-audio-user
