Am Mittwoch, den 02.12.2009, 12:57 -0800 schrieb Ken Restivo: > On Mon, Nov 30, 2009 at 10:21:13PM +0100, Bjoern Lindig wrote: > > Ok, I was thinking about that, too. But I cannot figure out how it works. > > > > Ok, I got it: for n = 3 and x = 4 (fourth round): 100 & 011 = 000. I must have > > had a brain stoppage, when I tried this last time ... > > > > Thank you very much. Now I feel ashamed that I try to work with faust, but > > don't even know how bitwise operation is done. Anyway, you should check out > > faust. It's realy awesome. > > > > The name of Faust is quite apt. Looking at (and trying to make sense out of) the C code that Faust has generated, makes me feel as though I have sold my soul to the devil. > > -ken I can't confirm that, Faust could be a key to open the door to DSP programming. The generated C++ Source is logical and easy to understand. Also, with Faust you could generate your (math) Ideas fast to a binary form. Only, if you don't like math and C++, it isn't your tool. hermann > ----------------- > > On Monday 30 November 2009 21:20:33 Arnold Krille wrote: > > > Disclaimer: I don't (yet) know faust > > > > > > On Monday 30 November 2009 20:38:12 Bjoern Lindig wrote: > > > > I have a problem understanding this piece of faust-code: > > > > index( n ) = &( n - 1 ) ~ + ( 1 ); > > > > It is from the faust-soft-computing.pdf. I do understand that it works > > > > like a counter and I think it should jump back to 0 when it reaches n - > > > > 1. But what exactly is the logical AND operator doing? > > > > > > I think its not a logical AND for expressions but a bitwise AND. Which > > > means that only the bits that are set in both arguments pass. Which would > > > make sense to have the counter wrap... > > > > > > Maybe that helps, > > > > > > Arnold > > > > > _______________________________________________ Linux-audio-user mailing list Linux-audio-user@xxxxxxxxxxxxxxxxxxxx http://lists.linuxaudio.org/mailman/listinfo/linux-audio-user
