fons adriaensen schrieb:
On Sun, Jan 29, 2006 at 10:55:05PM +0000, Folderol wrote:
No! It is definitely 1/c1 + 1/c2 ...
The only alternative I know of is 'product divided by sum' which is
often easier to use.
i.e.
(c1 x c2 x c3) / (c1 + c2 + c3)
Sorry, all wrong, as can be seen easily by considering the dimensions.
The first one is 1/Farad, the second Farad^2.
The rule is the same as for parallell resistors:
The inverse of the equivalent value is the sum of the inverses
of all individual values.
1/Ceq = 1/C1 + 1/C2 + 1/C3 + ...
or for just two of them
Ceq = (C1 * C2) / (C1 + C2)
with 3 caps, it would be:
ceq = (c1*c2*c3) / (c2*c3 + c1*c3 + c1*c2)
