On Sun, 16 Aug 2015 08:06:00 +0000 Fons Adriaensen <fons@xxxxxxxxxxxxxx> wrote: > On Sat, Aug 15, 2015 at 10:27:33PM +0100, Will Godfrey wrote: > > > As a matter of curiosity I wonder if we can work out what the actual difference > > is. Would the Xrun occur when there was a one frame difference, one period, or > > 1 buffer? It's running at 256 frames per period and 2 periods per buffer. The > > xruns occur every 11 minutes (and a few seconds). > > If you assume that an xrun occurs when the difference in samples is > one period, then the difference in sample frequency is P / T, with > P the period and T the time in seconds between xruns. > > With the values you give: > > dF = 256 / (11 * 60) =~ 0.39 Hz. > > You can measure this easily using jack_delay (or jack_iodelay). > The change in measured latency, in samples, per second is the > difference in sample rate. > > Ciao, > Thanks. Considering this is a mid-range unit V 'standard' motherboard sound, that's actually rather impressive. -- Will J Godfrey http://www.musically.me.uk Say you have a poem and I have a tune. Exchange them and we can both have a poem, a tune, and a song. _______________________________________________ Linux-audio-user mailing list Linux-audio-user@xxxxxxxxxxxxxxxxxxxx http://lists.linuxaudio.org/listinfo/linux-audio-user
