From: Yuri Norov <ynorov@xxxxxxxxxxx> If CPU runs isolated task, there's no any backlog on it, and so we don't need to flush it. Currently flush_all_backlogs() enqueues corresponding work on all CPUs including ones that run isolated tasks. It leads to breaking task isolation for nothing. In this patch, backlog flushing is enqueued only on non-isolated CPUs. Signed-off-by: Alex Belits <abelits@xxxxxxxxxxx> --- net/core/dev.c | 6 +++++- 1 file changed, 5 insertions(+), 1 deletion(-) diff --git a/net/core/dev.c b/net/core/dev.c index c6c985fe7b1b..6d32abb1f06d 100644 --- a/net/core/dev.c +++ b/net/core/dev.c @@ -74,6 +74,7 @@ #include <linux/cpu.h> #include <linux/types.h> #include <linux/kernel.h> +#include <linux/isolation.h> #include <linux/hash.h> #include <linux/slab.h> #include <linux/sched.h> @@ -5518,9 +5519,12 @@ static void flush_all_backlogs(void) get_online_cpus(); - for_each_online_cpu(cpu) + for_each_online_cpu(cpu) { + if (task_isolation_on_cpu(cpu)) + continue; queue_work_on(cpu, system_highpri_wq, per_cpu_ptr(&flush_works, cpu)); + } for_each_online_cpu(cpu) flush_work(per_cpu_ptr(&flush_works, cpu)); -- 2.20.1