On Tue, Feb 26, 2019 at 06:28:45AM -0800, Paul E. McKenney wrote: > Yes, this all is a bit on the insane side from a kernel viewpoint. > But the paper you found does not impose this; it has instead been there > for about 20 years, back before C and C++ admitted to the existence > of concurrency. But of course compilers are getting more aggressive, > and yes, some of the problems show up in single-threaded code. But that paper is from last year!! It has Peter Sewell on, I'm sure he's heard of concurrency. > The usual response is "then cast the pointers to intptr_t!" but of > course that breaks type checking. I tried laundering the pointer through intptr_t, but I can't seem to unbreak it. root@ivb-ep:~/tmp# gcc-8 -O2 -fno-strict-aliasing -o ptr ptr.c ; ./ptr p=0x55aacdc80034 q=0x55aacdc80034 x=1 y=2 *p=11 *q=2 root@ivb-ep:~/tmp# cat ptr.c #include <stdio.h> #include <string.h> #include <stdint.h> int y = 2, x = 1; int main (int argc, char **argv) { intptr_t P = (intptr_t)&x; intptr_t Q = (intptr_t)&y; P += sizeof(int); int *q = &y; printf("p=%p q=%p\n", (int*)P, (int*)Q); if (P == Q) { int *p = (int *)P; *p = 11; printf("x=%d y=%d *p=%d *q=%d\n", x, y, *p, *q); } }