On 2016年06月08日 17:22, Will Deacon wrote:
On Thu, Jun 02, 2016 at 06:09:08PM +0800, Pan Xinhui wrote:
strcut __qrwlock has different layout in big endian machine. we need set
the __qrwlock->wmode to NULL, and the address is not &lock->cnts in big
endian machine.
Do as what read unlock does. we are lucky that the __qrwlock->wmode's
val is _QW_LOCKED.
Doesn't this have wider implications for the qrwlocks, for example:
while ((cnts & _QW_WMASK) == _QW_LOCKED) { ... }
would actually end up looking at the wrong field of the lock?
I does not clearly understand your idea. :(
the condition in the while() is always true from the view of current code.
BUT if __qrwlock has same layout on the two endian machine, the while() will end up. :)
Shouldn't we just remove the #ifdef __LITTLE_ENDIAN stuff from __qrwlock,
given that all the struct members are u8?
No. that makes codes complex. for example
struct __qrwlock lock;
WRITE_ONCE(lock->wmode, _QW_WAITING);
if (atomic_(&lock->cnts) == _QW_WAITING) {
do_something();
}
IF you remove the #ifdef __LITTLE_ENDIAN stuff from __qrwlock.
codes above obviously will break. And we already have such code.
thanks
xinhui
Will
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