On Wed, Aug 15, 2012 at 02:47:00PM +0100, Arnd Bergmann wrote:
> On Tuesday 14 August 2012, Catalin Marinas wrote:
> > +pgd_t *pgd_alloc(struct mm_struct *mm)
> > +{
> > + pgd_t *new_pgd;
> > +
> > + new_pgd = (pgd_t *)__get_free_pages(GFP_KERNEL, PGD_ORDER);
> > + if (!new_pgd)
> > + return NULL;
> > +
> > + memset(new_pgd, 0, PAGE_SIZE << PGD_ORDER);
> > +
> > + return new_pgd;
> > +}
> > +
> > +void pgd_free(struct mm_struct *mm, pgd_t *pgd)
> > +{
> > + free_pages((unsigned long)pgd, PGD_ORDER);
> > +}
>
> According to the documentation, you should only need 8kb for the pgd on
> a 64kb page system. Is it required that you use up a full page here?
Not with the current virtual memory layout with 39-bit address space for
kernel. With 64K pages we can increase the address space to 42-bit while
still using 2-level page table, in which case a full page is used.
But for now I'll keep the same virtual memory layout and add a check on
(PTRS_PER_PGD * sizeof(pgd_t)), the compiler will choose the right path.
--
Catalin
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