On Tue, Jul 19, 2011 at 07:36:23AM +1000, Benjamin Herrenschmidt wrote:
> On Mon, 2011-07-18 at 07:37 -0700, Paul E. McKenney wrote:
> > On Mon, Jul 18, 2011 at 09:54:57PM +1000, Benjamin Herrenschmidt wrote:
> > > On Mon, 2011-07-18 at 13:23 +0200, Peter Zijlstra wrote:
> > >
> > > > So how are we going to solve this? Naively I'd think that
> > > > current_thread_info() is short for task_thread_info(current), and thus
> > > > the platforms for where this isn't true are broken.
> > > >
> > > > I mean, what use is the thread_info not of a thread?
> > > >
> > > > Comments?
> > >
> > > Thomas just hit a bug in the platform code of said platform (powerpc
> > > heh ?) :-)
> > >
> > > We do it right for hard IRQs and for some reason never did it right for
> > > softirqs.
> > >
> > > The code is like this for the former:
> > >
> > > static inline void handle_one_irq(unsigned int irq)
> > > {
> > >
> > > .../...
> > >
> > > call_handle_irq(irq, desc, irqtp, desc->handle_irq);
> > > current->thread.ksp_limit = saved_sp_limit;
> > > irqtp->task = NULL;
> > >
> > > /* Set any flag that may have been set on the
> > > * alternate stack
> > > */
> > > if (irqtp->flags)
> > > set_bits(irqtp->flags, &curtp->flags);
> > > }
> > >
> > > So what we need, I suppose is to add those two last line to
> > > do_softirq_onstack() as well.
> >
> > Hmmm... Would this explain preempt_count() inexplicably increasing by
> > three across a spin_unlock_irqrestore()? I ran into this situation when
> > testing on Power over the weekend.
>
> Hrm, no I don't see that happening no. The preempt count when exiting an
> irq or softirq stack should be the exact same as when entering it, which
> is why we don't bother copying it over. Do you see any case where that
> wouldn't hold ?
Nope, other than seeing preempt_count() transition from zero to three
across a spin_unlock_irqrestore() for no good reason that I could see.
Thanx, Paul
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