On Sat, Mar 30, 2019 at 05:50:20PM +0000, Jonathan Kowalski wrote:
> On Sat, Mar 30, 2019 at 5:24 PM Linus Torvalds
> <torvalds@xxxxxxxxxxxxxxxxxxxx> wrote:
> >
> > On Sat, Mar 30, 2019 at 10:12 AM Christian Brauner <christian@xxxxxxxxxx> wrote:
> > >
> > >
> > > To clarify, what the Android guys really wanted to be part of the api is
> > > a way to get race-free access to metadata associated with a given pidfd.
> > > And the idea was that *if and only if procfs is mounted* you could do:
> > >
> > > int pidfd = pidfd_open(1234, 0);
> > >
> > > int procfd = open("/proc", O_RDONLY | O_CLOEXEC);
> > > int procpidfd = ioctl(pidfd, PIDFD_TO_PROCFD, procfd);
> >
> > And my claim is that this is three system calls - one of them very
> > hacky - to just do
> >
> > int pidfd = open("/proc/%d", O_PATH);
> >
> > and you're done. It acts as the pidfd _and_ the way to get the
> > associated status files etc.
> >
> > So there is absolutely zero advantage to going through pidfd_open().
> >
> > No. No. No.
> >
> > So the *only* reason for "pidfd_open()" is if you don't have /proc in
> > the first place. In which case the whole PIDFD_TO_PROCFD is bogus.
> >
> > Yeah, yeah, if you want to avoid going through the pathname
> > translation, that's one thing, but if that's your aim, then you again
> > should also just admit that PIDFD_TO_PROCFD is disgusting and wrong,
> > and you're basically saying "ok, I'm not going to do /proc at all".
> >
> > So I'm ok with the whole "simpler, faster, no-proc pidfd", but then it
> > really has to be *SIMPLER* and *NO PROCFS*.
> >
>
> (Resending because accidently it wasn't a reply-all)
>
> If you go with pidfd_open, that should also mean you remove the
> ability to be able to use /proc/<PID> dir fds in pidfd_send_signal.
>
> Otherwise the semantics are hairy: I can only pidfd_open a task
> reachable from my active namespace, but somehow also be able to open a
You can easily setns() to another pid namespace and get a pidfd there.
That's how most namespace interactions work right now. We already had
that discussion.
