love Vick's short ones.
I use perl for tasks like this.
There is a perl module called File::Copy that is great for this.
something like.
opendir(HANDLE, "dir to read" ).
while ( $eachfile = readdir( HANDLE ) ) {
move( "$eachfile", "new_location/new_prefix_$eachfile
}
I can send you examples if you are interested.
You might also look at
http://www.stanford.edu/~epop/igal/
To organize your photos.
On Tue, 2 Nov 2004, Glynn Clements wrote:
>
> vick Julius wrote:
>
> > I have several directories (around 10) named ABC, DEF, GHI,...
> > Each directory contains more than 50 files named, for example, 1.jpg, 2.jpg,
> > 3.jpg,...50.jpg
> > These names are the same in each directory (this is what digital cameras do,
> > they give the same names...)
> > My problem is: I want to put all these files in the same directory, for
> > example, Photos, with the following names:
> > 1ABC.jpg, 2ABC.jpg, ...50ABC.jpg, 1DEF.jpg, 2DEF.jpg...50DEF.jpg,...
> > each image filename (such as 1.jpg) will be split and to insert the name of
> > the directory (such as ABC..) after the first part of the name and finally
> > append the extension (.jpg) to the filename.
>
> Two examples:
>
> for dir in ABC DEF GHI ; do
> for file in `(cd "$dir" && echo *.jpg)` ; do
> mv "$dir/$file" "Photos/${file%%.jpg}$dir.jpg"
> done
> done
>
> find . -type f | sed 's!^\./\(.*\)/\(.*\)\.jpg$!mv \1/\2.jpg Photos/\2\1.jpg!' | sh
>
> If any of the filenames contain spaces, it gets more complex.
>
>
--
Dan Kubilos __\o_ ^
K-8 Tech Coord
http://www.oxnardsd.org
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