Eliot, Wireless and Server Administrator, Great Lakes Internet wrote:
-----Original Message-----
From: lartc-bounces@xxxxxxxxxxxxxxx
[mailto:lartc-bounces@xxxxxxxxxxxxxxx] On Behalf Of
ramsurrunv@xxxxxxxxxxxx
Sent: Thursday, June 01, 2006 2:58 PM
To: lartc@xxxxxxxxxxxxxxx
Subject: Not understanding network setup!!
Hi to all,
...
First, 10.0.0.0/31 would be a network address. Second, a 31 bit subnet
is meaningless. It only offers two addresses, the network address at
10.0.0.0 and the broadcast address at 10.0.0.1. That leaves no available
addresses for host addresses. You probably mean /30 instead of /31. If
you were using a /30, then you would run:
ip addr add 10.0.0.1/30 dev eth1
ip addr add 10.0.0.5/30 dev eth2
ip addr add 10.0.0.9/30 dev teql0
The .1, .5, and .9 would be the first available addresses in their
respective subnets.
You probably mean /28 instead of /30:
ip addr add 10.0.0.9/28 dev teql0
Jarek P.
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