Hi, I'm have a linux router like this: ADSL modem-->(eth0) Linux Router (eth1)<--->LAN (6 hosts) Since I want to apply fairness to 6 hosts LAN, I have compiled kernel 2.4.20-8 with patch esfq 0.2 (and iproute2 with patch esfq too.) Next, I run folow script: -------------------------------------------- #!/usr/bin TC="/sbin/tc" $TC qdisc del dev eth1 root 2> /dev/null > /dev/null $TC qdisc add dev eth1 root handle 1:0 esfq perturb 0 hash dst $TC class show dev eth1 $TC qdisc show dev eth1 $TC filter show dev eth1 -------------------------------------------- And it shows me: qdisc esfq 1: quantum 1514b hash: dst Next, I make test from server to LAN hosts, and put iptraf in order to make measures. when I do: # nohup ping 192.168.1.3 -f & (a LAN HOST) # nohup ping 192.168.1.6 -f & (other LAN HOST) iptraf shows me equal bandwidth to that hosts. but if I repeat pings for one of that hosts: # nohup ping 192.168.1.6 -f & (other LAN HOST) # nohup ping 192.168.1.6 -f & (other LAN HOST) # nohup ping 192.168.1.6 -f & (other LAN HOST) iptraf shows me that 192.168.1.6 get more bandwidth that 192.168.1.3 Then seems ESFQ behaviour is like SFQ... what is wrong ???? I have ESFQ compiled like module. Also I've tried put ESFQ inside a HTB class but ESFQ behaviour is equal like above example. Where is the problem ? Thank you !!! Mac _______________________________________________ LARTC mailing list / LARTC@xxxxxxxxxxxxxxx http://mailman.ds9a.nl/mailman/listinfo/lartc HOWTO: http://lartc.org/
