Masse, Tom wrote: > > Let's say I have two Ethernet interfaces (eth0 and eth1). I am trying > to shape multiple TCP connections to 56K from one 100MBit pipe. > > CLIENT ---------- ETH0 -------- ETH1 ---------- SERVER > 192.168.1.1 192.168.1.254 172.16.1.254 172.16.1.1 > > For example, I want the client to be able to make multiple TCP > connections (.1.1:80, .1.1:8081, .1.1:8082) all at 56K from the > server, which obviously has the ability to deliver 100MBit. > > My CBQ file looks like so: > DEVICE=eth0,100MBit,10Mbit > RATE=56Kbit > WEIGHT=5Kbit > PRIO=5 > RULE=192.168.1.1/24:80 > RULE=192.168.1.1/24:8081 > RULE=192.168.1.1/24:8082 > RULE=192.168.1.1/24:8083 > RULE=192.168.1.1/24:8084 > RULE=192.168.1.1/24:8085 > > Is it possible to use iptables to make all the connections' > destination ports appear to be port 80? How, and to which interface, > should I apply the rules? > Tom, it is not possible to do so, if I understand your question. Take a look at http://www.netfilter.org/documentation to learn more about iptables. > Also, when is CBQ applied? Prerouting? Postrouting? Is it applied > pre- or post-routing specific to the interface, or to the kernel? > I suggest that you take a look at http://www.docum.org as there is a good FAQ about traffic control. You'll find a diagram that shows where traffic control applies. Stephane > > *Tom Masse* > Engineer, Network Operations > Gómez, Inc. > > T 781.768.2134 > F 781.466.1434 > > /Maximize Your Internet Channel Effectiveness/ > _http://www.gomez.com/_ >
