For the sake of a play-by-play (and why it wouldn't quite work right initially): 1) we need to dequeue a packet 2) we ask the 11 bit lower SFC for a packet. 3) it asks the upper SFC 4) the upper SFC takes the next bucket, based on IP, and gives us a packet. 5) the lower SFC takes that packet and has nothing else to work with, so it passes it on. ... So you're right :-) The two have to intercommunicate more ... So they have to be one. > Hmm I can't imagine that :) Probably it should be tested > > On Fri, 7 Jun 2002, Michael T. Babcock wrote: > > > > It can't be done. Outer SFC could do nothing with the packet. > > > It could only give it to inner one.... > > > > ... Ah, but it can choose which packet to give the inner > one. It would > > reorder the packets into a semi-fair order based on IP. > > > > > > ... SFC (8 bit hash against dest ip) > > > > | > > > > \-- SFC (11 bit hash against src ip, port, dest ip, port) > > > > | > > > > \-- dequeue ... _______________________________________________ LARTC mailing list / LARTC@mailman.ds9a.nl http://mailman.ds9a.nl/mailman/listinfo/lartc HOWTO: http://lartc.org/
