Re: [PATCH 08/27] nVMX: Hold a vmcs02 for each vmcs12

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 On 10/17/2010 12:07 PM, Nadav Har'El wrote:
In this patch we add a list of L0 (hardware) VMCSs, which we'll use to hold a
hardware VMCS for each active vmcs12 (i.e., for each L2 guest).

We call each of these L0 VMCSs a "vmcs02", as it is the VMCS that L0 uses
to run its nested guest L2.

+
+/*
+ * Allocate an L0 VMCS (vmcs02) for the current L1 VMCS (vmcs12), if one
+ * does not already exist. The allocation is done in L0 memory, so to avoid
+ * denial-of-service attack by guests, we limit the number of concurrently-
+ * allocated vmcss. A well-behaving L1 will VMCLEAR unused vmcs12s and not
+ * trigger this limit.
+ */
+static const int NESTED_MAX_VMCS = 256;

#define, top of file

+static int nested_create_current_vmcs(struct kvm_vcpu *vcpu)
+{
+	struct vmcs_list *new_l2_guest;
+	struct vmcs *vmcs02;
+
+	if (nested_get_current_vmcs(vcpu))
+		return 0; /* nothing to do - we already have a VMCS */
+
+	if (to_vmx(vcpu)->nested.vmcs02_num>= NESTED_MAX_VMCS)
+		return -ENOMEM;

Why not just free_l1_state()?

You can have just nested_get_current_vmcs() which creates the vmcs if necessary and returns an old if cached.

+
+	new_l2_guest = (struct vmcs_list *)
+		kmalloc(sizeof(struct vmcs_list), GFP_KERNEL);
+	if (!new_l2_guest)
+		return -ENOMEM;
+
+	vmcs02 = alloc_vmcs();
+	if (!vmcs02) {
+		kfree(new_l2_guest);
+		return -ENOMEM;
+	}
+
+	new_l2_guest->vmcs12_addr = to_vmx(vcpu)->nested.current_vmptr;
+	new_l2_guest->vmcs02 = vmcs02;
+	list_add(&(new_l2_guest->list),&(to_vmx(vcpu)->nested.vmcs02_list));
+	to_vmx(vcpu)->nested.vmcs02_num++;
+	return 0;
+}
+

@@ -4409,6 +4503,8 @@ static void vmx_free_vcpu(struct kvm_vcp
  		kunmap(to_vmx(vcpu)->nested.current_vmcs12_page);
  		nested_release_page(to_vmx(vcpu)->nested.current_vmcs12_page);
  	}
+	if (vmx->nested.vmxon)
+		free_l1_state(vcpu);

Can be called unconditionally.

  	vmx_free_vmcs(vcpu);
  	kfree(vmx->guest_msrs);
  	kvm_vcpu_uninit(vcpu);


--
error compiling committee.c: too many arguments to function

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