Re: [PATCH 1/2] x86 emulator: Add unary mul, imul, div, and idiv instructions

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 On 08/08/2010 07:53 AM, Mohammed Gamal wrote:
On Sun, Aug 8, 2010 at 2:34 PM, Avi Kivity<avi@xxxxxxxxxx>  wrote:
  On 08/08/2010 05:27 AM, Mohammed Gamal wrote:
This adds unary mul, imul, div, and idiv instructions (group 3 r/m 4-7).

Signed-off-by: Mohammed Gamal<m.gamal005@xxxxxxxxx>
---
  arch/x86/kvm/emulate.c |   41 ++++++++++++++++++++++++++++++++++++++++-
  1 files changed, 40 insertions(+), 1 deletions(-)

diff --git a/arch/x86/kvm/emulate.c b/arch/x86/kvm/emulate.c
index 7d78832..6d1ec53 100644
--- a/arch/x86/kvm/emulate.c
+++ b/arch/x86/kvm/emulate.c
@@ -315,6 +315,31 @@ struct group_dual {
                }                                                       \
        } while (0)

+#define __emulate_1op_src(_op, _src, _ax, _dx, _eflags, _suffix)
       \
Not just 1op - add rax_rdx to the name to indicate these are implicit
operands.

+       do {                                                            \
+               unsigned long _tmp;                                     \
+                                                                       \
+               __asm__ __volatile__ (                                  \
+                       _PRE_EFLAGS("0", "4", "1")                      \
+                       _op _suffix " %5; "                             \
+                       _POST_EFLAGS("0", "4", "1")                     \
+                       : "=m" (_eflags), "=&r" (_tmp),                 \
+                         "=a" (_ax), "=d" (_dx)                        \
+                       : "i" (EFLAGS_MASK), "m" ((_src).val),          \
+                         "a" (_ax), "d" (_dx));                        \
+       } while (0)
The byte form of the instruction doesn't update dx, and the word form
doesn't update edx[16:31].  So the "=a" and "=d" operands need to be "+a"
and "+d" so the compiler loads them before the operation is started.


I see you have "a" and "d" also in the inputs section. So the code is correct.

Please add a test to the effect, for example start with eax=0x12345678, and
multiply (byte size) 0x80 by 0x40,
We already have a value store in eax, so I can only either multiply it
by 0x80 or 0x40. Or do you mean we should have eax=0x12345680 and then
perhaps multply by 0x40 and make sure the upper 16 bits are preserved?

Yes.

--
I have a truly marvellous patch that fixes the bug which this
signature is too narrow to contain.

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