On Thursday, June 8, 2023 2:16 AM, Isaku Yamahata wrote: > On Mon, Jun 05, 2023 at 03:20:19PM +0000, "Wang, Wei W" > <wei.w.wang@xxxxxxxxx> wrote: > > > +static inline u64 kvm_seamcall(u64 op, u64 rcx, u64 rdx, u64 r8, u64 r9, > > > + struct tdx_module_output *out) { > > > + u64 ret; > > > + > > > + ret = __seamcall(op, rcx, rdx, r8, r9, out); > > > + if (unlikely(ret == TDX_SEAMCALL_UD)) { > > > + /* > > > + * TDX requires VMXON or #UD. In the case of reboot or > > > kexec, > > > + * VMX is made off (VMXOFF) by kvm reboot notifier, > > > + * kvm_reboot(), while TDs are still running. The callers > > > check > > > + * the returned error and complain. Suppress it by returning 0. > > > + */ > > > > Curious how do the callers check the returned error when " Suppress it > > by returning 0" here. > > It doesn't make sense for the caller to check the error and warn when > kvm_rebooting = true. > Let's make it "return kvm_rebooting ? 0 : ret;" instread of "return 0;". > Does it make sense? Seems no need. The comments look confusing, and not aligned to what the code achieves. From what I read: - if kvm_rebooting=true there: return 0 to caller and no error or warning happens - if kvm_rebooting=false there: crash the system via kvm_spurious_fault. In this non-rebooting case, I think the callers don’t get a chance to read the returned value and complain. Another thing is, have you double-checked that invocation of seamcalls indeed returns TDX_SEAMCALL_UD when VMX=off?