On Tue, Dec 20, 2022 at 09:23:17AM +0000, Arseniy Krasnov wrote:
On 20.12.2022 11:33, Stefano Garzarella wrote:
On Tue, Dec 20, 2022 at 07:14:27AM +0000, Arseniy Krasnov wrote:
On 19.12.2022 18:41, Stefano Garzarella wrote:
Hello!
Hi Arseniy,
On Sat, Dec 17, 2022 at 8:42 PM Arseniy Krasnov <AVKrasnov@xxxxxxxxxxxxxx> wrote:
Hello,
seems I found strange thing(may be a bug) where sender('tx' later) and
receiver('rx' later) could stuck forever. Potential fix is in the first
patch, second patch contains reproducer, based on vsock test suite.
Reproducer is simple: tx just sends data to rx by 'write() syscall, rx
dequeues it using 'read()' syscall and uses 'poll()' for waiting. I run
server in host and client in guest.
rx side params:
1) SO_VM_SOCKETS_BUFFER_SIZE is 256Kb(e.g. default).
2) SO_RCVLOWAT is 128Kb.
What happens in the reproducer step by step:
I put the values of the variables involved to facilitate understanding:
RX: buf_alloc = 256 KB; fwd_cnt = 0; last_fwd_cnt = 0;
free_space = buf_alloc - (fwd_cnt - last_fwd_cnt) = 256 KB
The credit update is sent if
free_space < VIRTIO_VSOCK_MAX_PKT_BUF_SIZE [64 KB]
1) tx tries to send 256Kb + 1 byte (in a single 'write()')
2) tx sends 256Kb, data reaches rx (rx_bytes == 256Kb)
3) tx waits for space in 'write()' to send last 1 byte
4) rx does poll(), (rx_bytes >= rcvlowat) 256Kb >= 128Kb, POLLIN is set
5) rx reads 64Kb, credit update is not sent due to *
RX: buf_alloc = 256 KB; fwd_cnt = 64 KB; last_fwd_cnt = 0;
free_space = 192 KB
6) rx does poll(), (rx_bytes >= rcvlowat) 192Kb >= 128Kb, POLLIN is set
7) rx reads 64Kb, credit update is not sent due to *
RX: buf_alloc = 256 KB; fwd_cnt = 128 KB; last_fwd_cnt = 0;
free_space = 128 KB
8) rx does poll(), (rx_bytes >= rcvlowat) 128Kb >= 128Kb, POLLIN is set
9) rx reads 64Kb, credit update is not sent due to *
Right, (free_space < VIRTIO_VSOCK_MAX_PKT_BUF_SIZE) is still false.
RX: buf_alloc = 256 KB; fwd_cnt = 196 KB; last_fwd_cnt = 0;
free_space = 64 KB
10) rx does poll(), (rx_bytes < rcvlowat) 64Kb < 128Kb, rx waits in poll()
I agree that the TX is stuck because we are not sending the credit
update, but also if RX sends the credit update at step 9, RX won't be
woken up at step 10, right?
Yes, RX will sleep, but TX will wake up and as we inform TX how much
free space we have, now there are two cases for TX:
1) send "small" rest of data(e.g. without blocking again), leave 'write()'
and continue execution. RX still waits in 'poll()'. Later TX will
send enough data to wake up RX.
2) send "big" rest of data - if rest is too big to leave 'write()' and TX
will wait again for the free space - it will be able to send enough data
to wake up RX as we compared 'rx_bytes' with rcvlowat value in RX.
Right, so I'd update the test to behave like this.
Sorry, You mean vsock_test? To cover TX waiting for free space at RX, thus checking
this kernel patch logic?
Yep, I mean the test that you added in this series.
And I'd explain better the problem we are going to fix in the commit message.
Ok
* is optimization in 'virtio_transport_stream_do_dequeue()' which
sends OP_CREDIT_UPDATE only when we have not too much space -
less than VIRTIO_VSOCK_MAX_PKT_BUF_SIZE.
Now tx side waits for space inside write() and rx waits in poll() for
'rx_bytes' to reach SO_RCVLOWAT value. Both sides will wait forever. I
think, possible fix is to send credit update not only when we have too
small space, but also when number of bytes in receive queue is smaller
than SO_RCVLOWAT thus not enough to wake up sleeping reader. I'm not
sure about correctness of this idea, but anyway - I think that problem
above exists. What do You think?
I'm not sure, I have to think more about it, but if RX reads less than
SO_RCVLOWAT, I expect it's normal to get to a case of stuck.
In this case we are only unstucking TX, but even if it sends that single
byte, RX is still stuck and not consuming it, so it was useless to wake
up TX if RX won't consume it anyway, right?
1) I think it is not useless, because we inform(not just wake up) TX that
there is free space at RX side - as i mentioned above.
2) Anyway i think that this situation is a little bit strange: TX thinks that
there is no free space at RX and waits for it, but there is free space at RX!
At the same time, RX waits in poll() forever - it is ready to get new portion
of data to return POLLIN, but TX "thinks" exactly opposite thing - RX is full
of data. Of course, if there will be just stalls in TX data handling - it will
be ok - just performance degradation, but TX stucks forever.
We did it to avoid a lot of credit update messages.
Yes, i see
Anyway I think here the main point is why RX is setting SO_RCVLOWAT to 128 KB and then reads only half of it?
So I think if the users set SO_RCVLOWAT to a value and then RX reads less then it, is expected to get stuck.
That a really interesting question, I've found nothing about this case in Google(not sure for 100%) or POSIX. But,
i can modify reproducer: it sets SO_RCVLOWAT to 128Kb BEFORE entering its last poll where it will stuck. In this
case behaviour looks more legal: it uses default SO_RCVLOWAT of 1, read 64Kb each time. Finally it sets SO_RCVLOWAT
to 128Kb(and imagine that it prepares 128Kb 'read()' buffer) and enters poll() - we will get same effect: TX will wait
for space, RX waits in 'poll()'.
Good point!
Anyway, since the change will not impact the default behaviour (SO_RCVLOWAT = 1) we can merge this patch, but IMHO we need to explain the case better and improve the test.
I see, of course I'm not sure about this change, just want to ask
someone who knows this code better
Yes, it's an RFC, so you did well! :-)
If RX woke up (e.g. SO_RCVLOWAT = 64KB) and read the remaining 64KB,
then it would still send the credit update even without this patch and
TX will send the 1 byte.
But how RX will wake up in this case? E.g. it calls poll() without timeout,
connection is established, RX ignores signal
RX will wake up because SO_RCVLOWAT is 64KB and there are 64 KB in the buffer. Then RX will read it and send the credit update to TX because
free_space is 0.
IIUC, i'm talking about 10 steps above, e.g. RX will never wake up,
because TX is waiting for space.
Yep, but if RX uses SO_RCVLOWAT = 64 KB instead of 128 KB (I mean if RX
reads all the bytes that it's waiting as it specified in SO_RCVLOWAT),
then RX will send the credit message.
But there is the case that you mentioned, when SO_RCVLOWAT is chagend
while executing.
Thanks,
Stefano
