On Thu, May 26, 2022, Marc Zyngier wrote: > > >> +{ > > >> + struct kvm_run *run = vcpu->run; > > >> + u64 dirty_quota = READ_ONCE(run->dirty_quota); > > >> + u64 pages_dirtied = vcpu->stat.generic.pages_dirtied; > > >> + > > >> + if (!dirty_quota || (pages_dirtied < dirty_quota)) > > >> + return 1; > > > What happens when page_dirtied becomes large and dirty_quota has to > > > wrap to allow further progress? > > Every time the quota is exhausted, userspace is expected to set it to > > pages_dirtied + new quota. So, pages_dirtied will always follow dirty > > quota. I'll be sending the qemu patches soon. Thanks. > > Right, so let's assume that page_dirtied=0xffffffffffffffff (yes, I > have dirtied that many pages). Really? Written that many bytes from a guest? Maybe. But actually marked that many pages dirty in hardware, let alone in KVM? And on a single CPU? By my back of the napkin math, a 4096 CPU system running at 16ghz with each CPU able to access one page of memory per cycle would take ~3 days to access 2^64 pages. Assuming a ridiculously optimistic ~20 cycles to walk page tables, fetch the cache line from memory, insert into the TLB, and mark the PTE dirty, that's still ~60 days to actually dirty that many pages in hardware. Let's again be comically optimistic and assume KVM can somehow propagate a dirty bit from hardware PTEs to the dirty bitmap/ring in another ~20 cycles. That brings us to ~1200 days. But the stat is per vCPU, so that actually means it would take ~13.8k years for a single vCPU/CPU to dirty 2^64 pages... running at a ludicrous 16ghz on a CPU with latencies that are a likely an order of magnitude faster than anything that exists today.