Re: [PATCH] KVM: x86: return 0 in case kvm_mmu_memory_cache has min number of objects

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Is my understanding correct?

On Tue, Sep 04, 2018 at 11:57:32PM +0800, Wei Yang wrote:
>The code tries to pre-allocate *min* number of objects, so it is ok to
>return 0 when the kvm_mmu_memory_cache meets the requirement.
>
>Signed-off-by: Wei Yang <richard.weiyang@xxxxxxxxx>
>---
> arch/x86/kvm/mmu.c | 4 ++--
> 1 file changed, 2 insertions(+), 2 deletions(-)
>
>diff --git a/arch/x86/kvm/mmu.c b/arch/x86/kvm/mmu.c
>index 28da8a9bd37b..aee296c579e1 100644
>--- a/arch/x86/kvm/mmu.c
>+++ b/arch/x86/kvm/mmu.c
>@@ -916,7 +916,7 @@ static int mmu_topup_memory_cache(struct kvm_mmu_memory_cache *cache,
> 	while (cache->nobjs < ARRAY_SIZE(cache->objects)) {
> 		obj = kmem_cache_zalloc(base_cache, GFP_KERNEL);
> 		if (!obj)
>-			return -ENOMEM;
>+			return (cache->nobjs >= min)?0 : -ENOMEM;
> 		cache->objects[cache->nobjs++] = obj;
> 	}
> 	return 0;
>@@ -944,7 +944,7 @@ static int mmu_topup_memory_cache_page(struct kvm_mmu_memory_cache *cache,
> 	while (cache->nobjs < ARRAY_SIZE(cache->objects)) {
> 		page = (void *)__get_free_page(GFP_KERNEL_ACCOUNT);
> 		if (!page)
>-			return -ENOMEM;
>+			return (cache->nobjs >= min)?0 : -ENOMEM;
> 		cache->objects[cache->nobjs++] = page;
> 	}
> 	return 0;
>-- 
>2.15.1

-- 
Wei Yang
Help you, Help me



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