Re: [PATCH v2 3/8] migration: show the statistics of compression

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* Peter Xu (peterx@xxxxxxxxxx) wrote:
> On Mon, Jul 23, 2018 at 03:39:18PM +0800, Xiao Guangrong wrote:
> > 
> > 
> > On 07/23/2018 12:36 PM, Peter Xu wrote:
> > > On Thu, Jul 19, 2018 at 08:15:15PM +0800, guangrong.xiao@xxxxxxxxx wrote:
> > > > @@ -1597,6 +1608,24 @@ static void migration_update_rates(RAMState *rs, int64_t end_time)
> > > >               rs->xbzrle_cache_miss_prev) / iter_count;
> > > >           rs->xbzrle_cache_miss_prev = xbzrle_counters.cache_miss;
> > > >       }
> > > > +
> > > > +    if (migrate_use_compression()) {
> > > > +        uint64_t comp_pages;
> > > > +
> > > > +        compression_counters.busy_rate = (double)(compression_counters.busy -
> > > > +            rs->compress_thread_busy_prev) / iter_count;
> > > 
> > > Here I'm not sure it's correct...
> > > 
> > > "iter_count" stands for ramstate.iterations.  It's increased per
> > > ram_find_and_save_block(), so IMHO it might contain multiple guest
> > 
> > ram_find_and_save_block() returns if a page is successfully posted and
> > it only posts 1 page out at one time.
> 
> ram_find_and_save_block() calls ram_save_host_page(), and we should be
> sending multiple guest pages in ram_save_host_page() if the host page
> is a huge page?
> 
> > 
> > > pages.  However compression_counters.busy should be per guest page.
> > > 
> > 
> > Actually, it's derived from xbzrle_counters.cache_miss_rate:
> >         xbzrle_counters.cache_miss_rate = (double)(xbzrle_counters.cache_miss -
> >             rs->xbzrle_cache_miss_prev) / iter_count;
> 
> Then this is suspecious to me too...

Actually; I think this isn't totally wrong;  iter_count is the *difference* in
iterations since the last time it was updated:

   uint64_t iter_count = rs->iterations - rs->iterations_prev;

        xbzrle_counters.cache_miss_rate = (double)(xbzrle_counters.cache_miss -
            rs->xbzrle_cache_miss_prev) / iter_count;

so this is:
      cache-misses-since-last-update
      ------------------------------
        iterations since last-update

so the 'miss_rate' is ~misses / iteration.
Although that doesn't really correspond to time.

Dave

> > 
> > > > +        rs->compress_thread_busy_prev = compression_counters.busy;
> > > > +
> > > > +        comp_pages = compression_counters.pages - rs->compress_pages_prev;
> > > > +        if (comp_pages) {
> > > > +            compression_counters.compression_rate =
> > > > +                (double)(compression_counters.reduced_size -
> > > > +                rs->compress_reduced_size_prev) /
> > > > +                (comp_pages * TARGET_PAGE_SIZE);
> > > > +            rs->compress_pages_prev = compression_counters.pages;
> > > > +            rs->compress_reduced_size_prev = compression_counters.reduced_size;
> > > > +        }
> > > > +    }
> > > >   }
> > > >   static void migration_bitmap_sync(RAMState *rs)
> > > > @@ -1872,6 +1901,9 @@ static void flush_compressed_data(RAMState *rs)
> > > >           qemu_mutex_lock(&comp_param[idx].mutex);
> > > >           if (!comp_param[idx].quit) {
> > > >               len = qemu_put_qemu_file(rs->f, comp_param[idx].file);
> > > > +            /* 8 means a header with RAM_SAVE_FLAG_CONTINUE. */
> > > > +            compression_counters.reduced_size += TARGET_PAGE_SIZE - len + 8;
> > > 
> > > I would agree with Dave here - why we store the "reduced size" instead
> > > of the size of the compressed data (which I think should be len - 8)?
> > > 
> > 
> > len-8 is the size of data after compressed rather than the data improved
> > by compression that is not straightforward for the user to see how much
> > the improvement is by applying compression.
> > 
> > Hmm... but it is not a big deal to me... :)
> 
> Yeah it might be a personal preference indeed. :)
> 
> It's just natural to do that this way for me since AFAIU the
> compression ratio is defined as:
> 
>                            compressed data size
>   compression ratio =    ------------------------
>                             original data size
> 
> > 
> > > Meanwhile, would a helper be nicer? Like:
> > 
> > Yup, that's nicer indeed.
> 
> Regards,
> 
> -- 
> Peter Xu
--
Dr. David Alan Gilbert / dgilbert@xxxxxxxxxx / Manchester, UK



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