On Wed, Dec 03, 2014 at 05:07:09PM +0100, Eric Auger wrote:
> Introduce __KVM_HAVE_ARCH_VIRTUAL_INTC_INITIALIZED define and
> associated kvm_arch_is_virtual_intc_initialized function. This latter
> allows to test whether the virtual interrupt controller is initialized
> and ready to accept virtual IRQ injection. On some architectures,
> the virtual interrupt controller is dynamically instantiated, justifying
> that kind of check.
>
> Signed-off-by: Eric Auger <eric.auger@xxxxxxxxxx>
> ---
> include/linux/kvm_host.h | 12 ++++++++++++
> 1 file changed, 12 insertions(+)
>
> diff --git a/include/linux/kvm_host.h b/include/linux/kvm_host.h
> index ea53b04..45fea3c 100644
> --- a/include/linux/kvm_host.h
> +++ b/include/linux/kvm_host.h
> @@ -696,6 +696,18 @@ static inline wait_queue_head_t *kvm_arch_vcpu_wq(struct kvm_vcpu *vcpu)
> #endif
> }
>
> +#ifndef __KVM_HAVE_ARCH_VIRTUAL_INTC_INITIALIZED
maybe you can drop the _virtual_ from all these names to make it
slightly shorter.
alternatively to this approach you could expose a function from the
irqfd layer that KVM intc implementations call into to say "I'm
ready"... Not sure if it would look nicer.
> +/*
> + * returns trues if the virtual interrupt controller is initialized and
> + * ready to accept virtual IRQ. On some architectures the virtual interrupt
> + * controller is dynamically instantiated and this is not always true.
> + */
> +static inline bool kvm_arch_is_virtual_intc_initialized(struct kvm *kvm)
> +{
> + return true;
> +}
don't you need to define a prototype if the architecture does define the
symbol?
> +#endif
> +
> int kvm_arch_init_vm(struct kvm *kvm, unsigned long type);
> void kvm_arch_destroy_vm(struct kvm *kvm);
> void kvm_arch_sync_events(struct kvm *kvm);
> --
> 1.9.1
>
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