On Thu, Jun 12, 2014 at 04:54:52PM -0400, Waiman Long wrote:
> If two tasks see the pending bit goes away and try to grab it with cmpxchg,
> there is no way we can avoid the contention. However, if some how the
> pending bit holder get the lock and another task set the pending bit before
> the current task, the spinlock value will become
> _Q_PENDING_VAL|_Q_LOCKED_VAL. The while loop will end and the code will
> blindly try to do a cmpxchg unless we check for this case before hand. This
> is what my code does by going back to the beginning of the for loop.
There is already a test for that; see the goto queue;
---
/*
* wait for in-progress pending->locked hand-overs
*
* 0,1,0 -> 0,0,1
*/
if (val == _Q_PENDING_VAL) {
while ((val = atomic_read(&lock->val)) == _Q_PENDING_VAL)
cpu_relax();
}
/*
* trylock || pending
*
* 0,0,0 -> 0,0,1 ; trylock
* 0,0,1 -> 0,1,1 ; pending
*/
for (;;) {
/*
* If we observe any contention; queue.
*/
if (val & ~_Q_LOCKED_MASK)
goto queue;
new = _Q_LOCKED_VAL;
if (val == new)
new |= _Q_PENDING_VAL;
old = atomic_cmpxchg(&lock->val, val, new);
if (old == val)
break;
val = old;
}
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